This is pretty easy to calculate, but I thought it was interesting because my instinct was that it almost didn't matter which one I did, but when I stopped to think about it, I realized that one attack was clearly better than the other. (technically, there are three attacks I could make, but one of them is absurd).
Game #441 • ElihuRoot (Von Pinn) vs. Boot2daHead (Jorgi) • Round #5
Your turn to attack
(4) p(6,6) (10) (20) (W)
Button: Von Pinn
Player: ElihuRoot
|
Player: Boot2daHead
Button: Jorgi
(4) (6) (8) (20) p(X)
 |
3 comments:
Ah yes, a chance of 4/10 as opposed to 6/12! I had to think about that one for a moment too before it became obvious. :)
I would have said 5/12 vs. 6/12, but yes. If you take the d6 with the p(6,6) you will win if you roll 6 or less: probability of success is 5/12 ~ 41.7% . if you take the d6 with the d10, you win if EITHER you roll 7 or more so B2dH must take the poison (probability 40%) OR if you roll 1-6, B2dH takes the d10, but rerolls a 6 and must then take the poision (probability 10%) -- so this gives a 50% chance.
Oh yes, forgot about the probability distribution of the twin die. XD
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